Probability Rules

Grade 11 · statistics · 24 practice problems · read aloud

🔊 Listen to this explanation

Probability Rules: Your Guide to "Chance"

Probability measures how likely an event is to happen, from 0 (impossible) to 1 (certain). We use rules to find the probability of combined events, like drawing cards or rolling dice. This is the foundation for understanding data and making predictions.

🔑 Key Rules

  • Addition Rule (OR): P(A or B) = P(A) + P(B) - P(A and B). Use when either event is good.
  • Multiplication Rule (AND): P(A and B) = P(A) × P(B|A). Use when you need both events to happen. "P(B|A)" is the probability of B given A already happened.
  • Complement Rule (NOT): P(not A) = 1 - P(A). Use to find the probability something does not happen.

🧩 Step-by-Step Guide

  1. Define the events. What are A and B?
  2. Identify the question. Are you finding P(A OR B) or P(A AND B)?
  3. Check if events are mutually exclusive (can't happen together). If yes, P(A and B)=0.
  4. Check if events are independent (one doesn't affect the other). If yes, P(B|A) = P(B).
  5. Apply the correct rule and calculate.

Example 1: The Addition Rule

In a class of 30 students, 18 play soccer, 15 play basketball, and 8 play both. What is P(a randomly chosen student plays soccer OR basketball)?

Step 1: Let S = soccer, B = basketball. P(S) = 18/30, P(B) = 15/30, P(S and B) = 8/30.
Step 2: We want P(S or B). They are NOT mutually exclusive (some play both).
Step 3: Apply Addition Rule: P(S or B) = P(S) + P(B) - P(S and B)
P(S or B) = (18/30) + (15/30) - (8/30) = 25/30 = 5/6.

Example 2: The Multiplication Rule

You have a bag with 5 red and 3 blue marbles. You pick two marbles without replacement. What is P(both are red)?

Step 1: Let R1 = first red, R2 = second red.
Step 2: We want P(R1 and R2). The events are dependent (no replacement).
Step 3: Apply Multiplication Rule: P(R1 and R2) = P(R1) × P(R2|R1)
P(R1) = 5/8. After one red is gone, P(R2|R1) = 4/7.
P(R1 and R2) = (5/8) × (4/7) = 20/56 = 5/14.

🚨 Common Mistakes

  • Adding when you should multiply: "OR" usually means add; "AND" usually means multiply.
  • Forgetting the overlap: Always subtract P(A and B) in the Addition Rule unless told events are mutually exclusive.
  • Ignoring dependence: If you don't replace an item, the probabilities change! Always ask, "Is this with or without replacement?"

💡 Tips & Tricks

  • Venn Diagrams: Draw them! They make overlapping events visual and help avoid addition rule errors.
  • Complement Shortcut: If "at least one" is hard to calculate, find P(none) and subtract from 1.
  • Word Clues: "Or" → Addition Rule. "And" / "Both" → Multiplication Rule.

📚 Practice Suggestions

1. Start with simple dice and coin problems.
2. Move to card problems and drawing items from a bag.
3. Create your own problems using your class roster (e.g., probability of choosing a person who plays an instrument OR a sport).
4. Always write out the rule you are using before plugging in numbers.

Practice problems

6 of the 24, worked through step by step — try them before opening the answer.

1 P(Ava) = 0.75, P(Noah|Ava) = 0.80, P(Ava and Noah) = ?

Hint: Use the multiplication rule for conditional probability. For example, if P(X) = 0.5 and P(Y|X) = 0.4, then P(X and Y) = P(X) × P(Y|X).

Show the answer

Answer: 0.6

  1. Recall the multiplication rule for conditional probability: P(A and B) = P(A) × P(B|A)
  2. Substitute the given values: P(Ava and Noah) = P(Ava) × P(Noah|Ava)
  3. Calculate: P(Ava and Noah) = 0.75 × 0.80
  4. Multiply: 0.75 × 0.80 = 0.60
  5. The probability that both events occur is 0.60

The answer is 0.6.

2 P(A) = 0.85, P(B) = 0.72, P(A and B) = 0.612. Find P(A|B).

Hint: Remember the formula for conditional probability: P(A|B) = P(A and B) / P(B). Use the given probabilities to calculate this ratio.

Show the answer

Answer: 0.85

  1. Write the conditional probability formula: P(A|B) = P(A and B) / P(B)
  2. Substitute the given values: P(A|B) = 0.612 / 0.72
  3. Calculate the division: 0.612 ÷ 0.72 = 0.85
  4. The conditional probability P(A|B) is 0.85

3 P(Hana) = 0.48, P(Matiu|Hana) = 0.64, P(Hana and Matiu) = ?

Hint: Use the multiplication rule for conditional probability. For example, if P(X) = 0.6 and P(Y|X) = 0.5, then P(X and Y) = P(X) × P(Y|X).

Show the answer

Answer: 0.3072

  1. Recall the multiplication rule for conditional probability: P(A and B) = P(A) × P(B|A).
  2. Substitute the given values: P(Hana and Matiu) = P(Hana) × P(Matiu|Hana).
  3. Calculate: 0.48 × 0.64 = 0.3072.
  4. Therefore, P(Hana and Matiu) = 0.3072.

4 P(Aroha) = 0.85, P(Tane|Aroha) = 0.72, P(Aroha and Tane) = ?

Hint: Use the multiplication rule for conditional probability. For example, if P(X) = 0.6 and P(Y|X) = 0.5, then P(X and Y) = P(X) × P(Y|X).

Show the answer

Answer: 0.612

  1. Recall the multiplication rule for conditional probability: P(A and B) = P(A) × P(B|A).
  2. Substitute the given values: P(Aroha and Tane) = P(Aroha) × P(Tane|Aroha).
  3. Calculate: 0.85 × 0.72 = 0.612.
  4. The probability that both events occur is 0.612.

5 P(Ava) = 0.87, P(Noah) = 0.65, P(Ava and Noah) = 0.5655. Find P(Ava|Noah).

Hint: Remember that conditional probability is calculated by dividing the probability of both events occurring by the probability of the given event.

Show the answer

Answer: 0.87

  1. Write the conditional probability formula: P(Ava|Noah) = P(Ava and Noah) / P(Noah)
  2. Substitute the given values: P(Ava|Noah) = 0.5655 / 0.65
  3. Perform the division: 0.5655 ÷ 0.65 = 0.87
  4. The conditional probability is 0.87

6 P(Aroha) = 0.92, P(Tane) = 0.85, P(Aroha and Tane) = 0.782. Find P(Aroha|Tane).

Hint: Use the conditional probability formula: P(A|B) = P(A and B) / P(B). Remember that this formula calculates the probability of event A occurring given that event B has already occurred.

Show the answer

Answer: 0.92

  1. Write the conditional probability formula: P(Aroha|Tane) = P(Aroha and Tane) / P(Tane)
  2. Substitute the given values: P(Aroha|Tane) = 0.782 / 0.85
  3. Calculate the division: 0.782 ÷ 0.85 = 0.92
  4. The conditional probability P(Aroha|Tane) is 0.92
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