Trigonometric Identities

Grade 12 · algebra · 67 practice problems · read aloud

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Trigonometric Identities

What Are They and Why Use Them?

Trigonometric identities are equations that are true for all values of the variable. They are the fundamental tools for simplifying expressions, solving equations, and proving mathematical statements. Mastering them is crucial for calculus, physics, and engineering.

Core Identities to Know

  • Pythagorean: sin²θ + cos²θ = 1
  • Reciprocal: cscθ = 1/sinθ, secθ = 1/cosθ, cotθ = 1/tanθ
  • Quotient: tanθ = sinθ/cosθ, cotθ = cosθ/sinθ
  • Even/Odd: cos(-θ)=cosθ (even), sin(-θ)=-sinθ (odd)

Step-by-Step Problem Solving

  1. Identify Goal: Are you simplifying, verifying, or solving?
  2. Know Your Tools: Recall the fundamental identities listed above.
  3. Manipulate Strategically: Rewrite everything in terms of sine and cosine. Look for Pythagorean forms.
  4. Simplify Stepwise: Combine fractions and cancel common factors carefully.

Example 1: Simplify (1 - cos²θ) / sinθ

Step 1: Recognize that 1 - cos²θ is equal to sin²θ by the Pythagorean Identity.
Step 2: Substitute: (sin²θ) / sinθ.
Step 3: Simplify by canceling one sinθ: sinθ.

Example 2: Verify secθ cosθ = 1

Step 1: Rewrite secant in terms of cosine: secθ = 1/cosθ.
Step 2: Substitute: (1/cosθ) * cosθ.
Step 3: The cosθ terms cancel, leaving 1 = 1. Verified! ✅

Common Mistakes to Avoid

  • Misapplying Identities: sin(2θ) is NOT 2sinθ. This is a common confusion with the double-angle identity.
  • Algebra Errors: Forgetting to find a common denominator when adding fractions.
  • Domain Issues: Canceling terms without ensuring they are not zero (e.g., canceling sinθ when it could be 0).

Tips & Tricks 🧠

  • Memory Aid: For Pythagorean identities, remember the base: sin²θ + cos²θ = 1. Divide through by sin²θ or cos²θ to get the other forms.
  • Strategy: When in doubt, convert everything to sines and cosines. This often reveals the path forward.
  • Practice Patterns: Look for expressions like (1 - cos²θ) or (sec²θ - 1); they are often hidden Pythagorean identities.

How to Practice

Start by memorizing the core identities. Then, work through textbook problems focused on simplification and verification. Create flashcards for the identities. Finally, challenge yourself with problems that require you to prove more complex identities, writing each step clearly and justifying it with a specific identity.

Practice problems

6 of the 67, worked through step by step — try them before opening the answer.

1 Verify: (csc³θ - cscθ) / (cot²θ) = cscθ.

Hint: Factor the numerator using a common factor of cscθ, then use the Pythagorean identity relating csc²θ and cot²θ.

Show the answer

Answer: cscθ

Start with the left side: (csc³θ - cscθ) / cot²θ. Factor cscθ from the numerator: cscθ(csc²θ - 1) / cot²θ. Use the identity csc²θ - 1 = cot²θ. Substitute: cscθ(cot²θ) / cot²θ. Cancel cot²θ (provided cot²θ ≠ 0, i.e., θ not a multiple of π/2). Result: cscθ. The left side simplifies to cscθ, which equals the right side. Thus the identity is verified.

2 Verify: (sec²θ - 1) / (tan²θ + 1) = sin²θ.

Hint: Rewrite sec²θ and tan²θ in terms of sine and cosine, then simplify the fraction using the Pythagorean identity.

Show the answer

Answer: sin²θ

  1. Use identities: sec²θ = 1/cos²θ, tan²θ = sin²θ/cos²θ.
  2. Substitute: (1/cos²θ - 1) / (sin²θ/cos²θ + 1).
  3. Combine numerator: (1 - cos²θ)/cos²θ = sin²θ/cos²θ (since 1 - cos²θ = sin²θ).
  4. Combine denominator: (sin²θ + cos²θ)/cos²θ = 1/cos²θ (since sin²θ + cos²θ = 1).
  5. The left side becomes (sin²θ/cos²θ) ÷ (1/cos²θ) = (sin²θ/cos²θ) * (cos²θ/1) = sin²θ. Thus, left side equals right side, verifying the identity.

Start with the left side: (sec²θ - 1) / (tan²θ + 1).

3 Verify: (sin⁴θ - cos⁴θ) / (sin²θ - cos²θ) = 1

Hint: Factor the numerator as a difference of squares, then simplify with the denominator.

Show the answer

Answer: 1

  1. Start with the left side: (sin⁴θ - cos⁴θ) / (sin²θ - cos²θ)
  2. Factor the numerator as a difference of squares: sin⁴θ - cos⁴θ = (sin²θ - cos²θ)(sin²θ + cos²θ)
  3. Rewrite the expression: [(sin²θ - cos²θ)(sin²θ + cos²θ)] / (sin²θ - cos²θ)
  4. Cancel the common factor (sin²θ - cos²θ) (provided sin²θ ≠ cos²θ): = sin²θ + cos²θ
  5. Use the Pythagorean identity: sin²θ + cos²θ = 1 Thus, the left side simplifies to 1, which equals the right side. The identity is verified.

4 Verify: (sin⁴θ - cos⁴θ) / (sin²θ - cos²θ) = 1.

Hint: Factor the numerator as a difference of squares, then simplify with the denominator.

Show the answer

Answer: 1

  1. Factor the numerator sin⁴θ - cos⁴θ as (sin²θ - cos²θ)(sin²θ + cos²θ).
  2. The expression becomes [(sin²θ - cos²θ)(sin²θ + cos²θ)] / (sin²θ - cos²θ).
  3. Cancel the common factor (sin²θ - cos²θ), provided sin²θ ≠ cos²θ.
  4. Use the Pythagorean identity sin²θ + cos²θ = 1.
  5. The result is 1.

The answer is 1.

5 Verify: (csc²θ - cot²θ) / (sec²θ - tan²θ) = 1.

Hint: Use the Pythagorean identities for csc²θ and sec²θ to rewrite the numerator and denominator in terms of 1.

Show the answer

Answer: 1

  1. Recall the Pythagorean identities: csc²θ = 1 + cot²θ and sec²θ = 1 + tan²θ.
  2. Substitute into the numerator: csc²θ - cot²θ = (1 + cot²θ) - cot²θ = 1.
  3. Substitute into the denominator: sec²θ - tan²θ = (1 + tan²θ) - tan²θ = 1.
  4. The expression becomes 1 / 1 = 1. Therefore, the identity is verified: (csc²θ - cot²θ) / (sec²θ - tan²θ) = 1.

6 Verify: (sec⁴θ - tan⁴θ) / (sec²θ + tan²θ) = 1.

Hint: Factor the numerator as a difference of squares, then simplify using the Pythagorean identity.

Show the answer

Answer: 1

Start with the left side: (sec⁴θ - tan⁴θ) / (sec²θ + tan²θ). Factor the numerator as a difference of squares: sec⁴θ - tan⁴θ = (sec²θ - tan²θ)(sec²θ + tan²θ). Cancel the common factor (sec²θ + tan²θ) in numerator and denominator: (sec²θ - tan²θ)(sec²θ + tan²θ) / (sec²θ + tan²θ) = sec²θ - tan²θ. Use the Pythagorean identity: sec²θ = 1 + tan²θ, so sec²θ - tan²θ = 1. Thus the left side simplifies to 1, which equals the right side. The identity is verified.

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