Expand Linear Expressions

Grade 7 ยท algebra ยท 72 practice problems ยท read aloud

๐Ÿ”Š Listen to this explanation

Expand Linear Expressions

๐Ÿง  What is Expanding and Why is it Useful?

Expanding a linear expression means using the distributive property to remove parentheses. You multiply the term outside the parentheses by every term inside. This is a crucial skill in algebra because it helps you simplify expressions and solve equations more easily.

๐Ÿ“ Step-by-Step Guide

  1. Identify the number or term outside the parentheses.
  2. Multiply that outside term by the first term inside the parentheses.
  3. Multiply the same outside term by the second term inside the parentheses.
  4. Write the new expression by combining the products with a plus or minus sign.

๐Ÿ” Visual Examples

Example 1: Expand 5(x + 2)

  1. Multiply 5 by x: 5 ร— x = 5x
  2. Multiply 5 by 2: 5 ร— 2 = 10
  3. Combine: 5x + 10

Example 2: Expand -3(2y - 4)

  1. Multiply -3 by 2y: -3 ร— 2y = -6y
  2. Multiply -3 by -4: -3 ร— -4 = +12
  3. Combine: -6y + 12

๐Ÿšจ Common Mistakes

  • Forgetting the Sign: When the number outside is negative (like in Example 2), students often forget to multiply the signs correctly. Remember: negative ร— negative = positive!
  • Only Multiplying the First Term: Make sure you multiply the outside term by every term inside the parentheses.

๐Ÿ’ก Tips & Tricks

  • Use the acronym D.P.M. (Distribute, Multiply, Multiply) to remember the steps.
  • Draw arrows from the outside term to each term inside the parentheses as a visual reminder.
  • Always double-check your signs! They are the most common source of errors.

๐ŸŽฏ Practice Suggestions

Start simple! Practice with positive numbers first, like 4(a + 3). Once you're comfortable, move to expressions with negative numbers, like -2(x - 5). You can create your own practice problems or use online worksheets. Try to do at least 5 problems a day to build your confidence and speed.

Practice problems

6 of the 72, worked through step by step โ€” try them before opening the answer.

1 3(2x + 5) - 4(x - 3) = ?

Hint: Apply the distributive property to each term, then combine like terms by adding or subtracting coefficients of the same variable and constants.

Show the answer

Answer: 2x + 27

  1. Distribute the 3 into the first parentheses** 3 ร— 2x = 6x 3 ร— 5 = 15 So 3(2x + 5) becomes 6x + 15. **
  2. Distribute the -4 into the second parentheses** -4 ร— x = -4x -4 ร— (-3) = +12 So -4(x - 3) becomes -4x + 12. **
  3. Rewrite the expression with the distributed terms** 6x + 15 - 4x + 12 **
  4. Combine like terms** For the x terms: 6x - 4x = 2x For the constant terms: 15 + 12 = 27 **
  5. Write the final simplified expression** 2x + 27 **Final answer:** 2x + 27

Let's solve the problem step-by-step. We start with: 3(2x + 5) - 4(x - 3) **

2 3(2x - 5) + 4(x + 3) = ?

Hint: Apply the distributive property to each term, then combine like terms by adding coefficients of variables and constants separately.

Show the answer

Answer: 10x - 3

  1. Distribute the 3 into the first parentheses** 3 * 2x = 6x 3 * (-5) = -15 So, 3(2x - 5) becomes 6x - 15. **
  2. Distribute the 4 into the second parentheses** 4 * x = 4x 4 * 3 = 12 So, 4(x + 3) becomes 4x + 12. **
  3. Write the expression after distribution** 6x - 15 + 4x + 12 **
  4. Combine like terms** First, combine the x terms: 6x + 4x = 10x Then, combine the constant terms: -15 + 12 = -3 **
  5. Write the final simplified expression** 10x - 3 **Final Answer:** 10x - 3

Let's solve the problem step by step. We start with: 3(2x - 5) + 4(x + 3) **

3 2(3x + 4) - 5(x - 2) = ?

Hint: Apply the distributive property to each term before combining like terms. Remember to distribute negative signs carefully.

Show the answer

Answer: x + 18

  1. Apply the distributive property** First term: 2(3x + 4) = 2 * 3x + 2 * 4 = 6x + 8 Second term: -5(x - 2) = -5 * x + (-5) * (-2) = -5x + 10 So now we have: 6x + 8 - 5x + 10 **
  2. Combine like terms** For the x terms: 6x - 5x = 1x (or just x) For the constant terms: 8 + 10 = 18 **
  3. Write the final expression** x + 18 **Final answer:** x + 18

Let's solve step by step. We start with: 2(3x + 4) - 5(x - 2) = ? **

4 4(2x - 7) + 3(5 - x) = ?

Hint: Apply the distributive property to each term, then combine like terms by adding or subtracting coefficients of the same variable and constants

Show the answer

Answer: 5x - 13

  1. Distribute 4 to both terms inside the first parentheses: 4 ร— 2x = 8x and 4 ร— (-7) = -28
  2. Distribute 3 to both terms inside the second parentheses: 3 ร— 5 = 15 and 3 ร— (-x) = -3x
  3. Write the expanded expression: 8x - 28 + 15 - 3x
  4. Combine like terms for x: 8x - 3x = 5x
  5. Combine constant terms: -28 + 15 = -13
  6. Write the simplified expression: 5x - 13

The answer is 5x - 13.

5 4(3x - 7) - 2(5x + 4) = ?

Hint: Apply the distributive property to each term, then combine like terms by adding or subtracting coefficients of x and constants separately.

Show the answer

Answer: 2x - 36

  1. Distribute 4 to both terms inside the first parentheses: 4 ร— 3x = 12x and 4 ร— (-7) = -28, so we get 12x - 28
  2. Distribute -2 to both terms inside the second parentheses: -2 ร— 5x = -10x and -2 ร— 4 = -8, so we get -10x - 8
  3. Combine all terms: (12x - 28) + (-10x - 8) = 12x - 28 - 10x - 8
  4. Combine like terms: (12x - 10x) + (-28 - 8) = 2x - 36

The answer is 2x - 36.

6 3(4x - 7) + 2(5x + 3) = ?

Hint: Apply the distributive property to each term, then combine like terms. For example, with 2(a + b) - 3(c - d), distribute first, then combine.

Show the answer

Answer: 22x - 15

  1. Distribute 3 to both terms inside the first parentheses: 3 ร— 4x = 12x and 3 ร— (-7) = -21, so we get 12x - 21
  2. Distribute 2 to both terms inside the second parentheses: 2 ร— 5x = 10x and 2 ร— 3 = 6, so we get 10x + 6
  3. Combine all terms: (12x - 21) + (10x + 6)
  4. Combine like terms: 12x + 10x = 22x and -21 + 6 = -15
  5. The simplified expression is 22x - 15
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