Systems Word Problems

Grade 8 ยท algebra ยท 101 practice problems ยท read aloud

๐Ÿ”Š Listen to this explanation

Systems of Equations: Word Problems

๐Ÿง  What Are Systems Word Problems?

A system of equations is when you have two or more equations working together. We use them to solve real-world problems where there are two unknown values that are related to each other in different ways. For example, figuring out how many adults and children are in a group based on ticket prices and total sales.

๐Ÿ“ How to Solve Systems Word Problems

  1. Step 1: Define Your Variables. Figure out what the two unknowns are and assign them letters (like x and y).
  2. Step 2: Write the Equations. Translate the words in the problem into two separate mathematical equations.
  3. Step 3: Choose a Solution Method. Decide whether to use substitution (solving for one variable and plugging it in) or elimination (adding or subtracting equations to cancel a variable).
  4. Step 4: Solve the System. Find the values of both variables.
  5. Step 5: Check Your Answer. Plug your solution back into the original word problem to make sure it makes sense!

๐Ÿ” Worked Examples

Example 1: The Concert Tickets

Problem: Tickets for a concert are $5 for students and $10 for adults. 100 tickets were sold, and the total revenue was $650. How many of each ticket were sold?

Solution:

  1. Define: Let s = number of student tickets, a = number of adult tickets.
  2. Equations:
    Equation 1 (Total Tickets): s + a = 100
    Equation 2 (Total Money): 5s + 10a = 650
  3. Solve (using substitution):
    Solve the first equation for s: s = 100 - a
    Substitute into the second: 5(100 - a) + 10a = 650
    Simplify: 500 - 5a + 10a = 650 โ†’ 500 + 5a = 650
    Solve: 5a = 150 โ†’ a = 30
    Then: s = 100 - 30 = 70
  4. Answer: 70 student tickets and 30 adult tickets.

โš ๏ธ Common Mistakes to Avoid

  • Mixing up variables: Be clear about what x and y stand for. Write it down!
  • Incorrect equations: Double-check that your equations accurately represent the problem. Does your money equation use the correct prices?
  • Forgetting to find both values: After you find x, don't forget to plug it back in to find y.
  • Not checking the solution: Always verify your answer makes sense in the context of the story.

๐Ÿ’ก Tips & Tricks

  • Look for "total" phrases: Phrases like "the total number is..." often give you your first equation (x + y = total).
  • Look for value phrases: Phrases involving money or value give you your second equation ((price1)(x) + (price2)(y) = total value).
  • Use elimination when the coefficients of one variable are the same or opposites.
  • Use substitution when one variable is already isolated or easily isolated.

๐ŸŽฏ How to Practice

Start with simple problems involving two types of items (tickets, coins, people). Practice writing the equations from the words before you even try to solve them. Create your own word problems for a friend to solve! Use online platforms like Khan Academy for instant feedback on your practice.

Practice problems

6 of the 101, worked through step by step โ€” try them before opening the answer.

1 (2x + 3y = 12) and (3x - 2y = 5) = ?

Hint: When solving a system of equations, you can use elimination by making coefficients of one variable opposites, or substitution by solving one equation for a variable and plugging into the other.

Show the answer

Answer: x = 3, y = 2

  1. Make the coefficients of y the same in both equations. Multiply equation (1) by 2: 2*(2x + 3y) = 2*12 4x + 6y = 24 Multiply equation (2) by 3: 3*(3x - 2y) = 3*5 9x - 6y = 15
  2. Add the two new equations to eliminate y. (4x + 6y) + (9x - 6y) = 24 + 15 4x + 9x + 6y - 6y = 39 13x = 39
  3. Solve for x. x = 39 / 13 x = 3
  4. Substitute x = 3 into equation (1) to find y. 2*(3) + 3y = 12 6 + 3y = 12 3y = 12 - 6 3y = 6 y = 6 / 3 y = 2
  5. Check in equation (2). 3*(3) - 2*(2) = 9 - 4 = 5, which matches. Final answer: x = 3, y = 2

We are given the system of equations: (1) 2x + 3y = 12 (2) 3x - 2y = 5 We will solve by elimination.

2 2x + 3y = 12 and x - y = 1, find x and y

Hint: You can use substitution by expressing one variable in terms of the other from the simpler equation, then substitute into the other equation.

Show the answer

Answer: x = 3, y = 2

  1. Solve one equation for one variable** From Equation 2: x - y = 1 So, x = y + 1 --- **
  2. Substitute into the other equation** Substitute x = y + 1 into Equation 1: 2(y + 1) + 3y = 12 --- **
  3. Simplify and solve for y** 2y + 2 + 3y = 12 5y + 2 = 12 5y = 12 - 2 5y = 10 y = 10 / 5 y = 2 --- **
  4. Solve for x** From x = y + 1: x = 2 + 1 x = 3 --- **
  5. Check the solution** In Equation 1: 2(3) + 3(2) = 6 + 6 = 12 โœ“ In Equation 2: 3 - 2 = 1 โœ“ --- **Final Answer:** x = 3, y = 2

We are given two equations: Equation 1: 2x + 3y = 12 Equation 2: x - y = 1 We need to find the values of x and y. --- **

3 3x + 2y = 16 and 2x - y = 3, find x and y

Hint: You can use substitution or elimination method. Try solving one equation for one variable and substituting into the other equation.

Show the answer

Answer: x = 2, y = 1

  1. Solve the second equation for y: 2x - y = 3 โ†’ -y = 3 - 2x โ†’ y = 2x - 3
  2. Substitute y = 2x - 3 into the first equation: 3x + 2(2x - 3) = 16
  3. Simplify: 3x + 4x - 6 = 16 โ†’ 7x - 6 = 16
  4. Solve for x: 7x = 22 โ†’ x = 22/7 โ†’ x = 2
  5. Substitute x = 2 into y = 2x - 3: y = 2(2) - 3 = 4 - 3 = 1
  6. Verify: 3(2) + 2(1) = 6 + 2 = 8 (check), 2(2) - 1 = 4 - 1 = 3 (check) The solution is x = 2, y = 1.

4 3x + 2y = 19 and 2x - y = 6, find x and y

Hint: Try using substitution by solving one equation for a variable, then substituting into the other equation

Show the answer

Answer: x = 5, y = 4

  1. Solve the second equation for y: 2x - y = 6 โ†’ -y = 6 - 2x โ†’ y = 2x - 6
  2. Substitute y = 2x - 6 into the first equation: 3x + 2(2x - 6) = 19
  3. Simplify: 3x + 4x - 12 = 19 โ†’ 7x - 12 = 19
  4. Solve for x: 7x = 31 โ†’ x = 31/7 โ†’ x = 5
  5. Substitute x = 5 into y = 2x - 6: y = 2(5) - 6 = 10 - 6 = 4
  6. Check: 3(5) + 2(4) = 15 + 8 = 23, and 2(5) - 4 = 10 - 4 = 6 The solution is x = 5, y = 4.

5 2x + 3y = 12 and 4x - y = 10, find x and y

Hint: You can use substitution or elimination method to solve for the variables. Try to eliminate one variable by making coefficients equal.

Show the answer

Answer: x = 3, y = 2

  1. Solve one equation for one variable. From equation (2): 4x - y = 10 Add y to both sides: 4x = 10 + y Subtract 10 from both sides: y = 4x - 10
  2. Substitute y = 4x - 10 into equation (1). Equation (1): 2x + 3y = 12 Replace y with (4x - 10): 2x + 3(4x - 10) = 12
  3. Simplify and solve for x. 2x + 12x - 30 = 12 14x - 30 = 12 Add 30 to both sides: 14x = 42 Divide both sides by 14: x = 42/14 x = 3
  4. Substitute x = 3 into y = 4x - 10. y = 4(3) - 10 y = 12 - 10 y = 2
  5. Check the solution in both original equations. In (1): 2(3) + 3(2) = 6 + 6 = 12 โœ“ In (2): 4(3) - 2 = 12 - 2 = 10 โœ“ Final answer: x = 3, y = 2

We are given the system of equations: (1) 2x + 3y = 12 (2) 4x - y = 10

6 2x + 3y = 12 and 3x - 2y = 5, find x and y

Hint: You can use elimination by making coefficients of one variable match, then add or subtract equations to eliminate that variable.

Show the answer

Answer: x = 3, y = 2

  1. Make the coefficients of y the same in both equations. Multiply Equation 1 by 2: 2 * (2x + 3y) = 2 * 12 4x + 6y = 24 Multiply Equation 2 by 3: 3 * (3x - 2y) = 3 * 5 9x - 6y = 15
  2. Add these two new equations to eliminate y. (4x + 6y) + (9x - 6y) = 24 + 15 4x + 9x + 6y - 6y = 39 13x = 39
  3. Solve for x. x = 39 / 13 x = 3
  4. Substitute x = 3 into Equation 1 to find y. 2(3) + 3y = 12 6 + 3y = 12 3y = 12 - 6 3y = 6 y = 6 / 3 y = 2
  5. Check in Equation 2. 3(3) - 2(2) = 9 - 4 = 5, which matches. Final answer: x = 3, y = 2

We are given two equations: Equation 1: 2x + 3y = 12 Equation 2: 3x - 2y = 5 We will solve by elimination.

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