Compound Inequalities

Grade 9 · algebra · 101 practice problems · read aloud

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What Are Compound Inequalities? 🤔

A compound inequality is a sentence with two inequality statements joined by either the word "AND" or the word "OR". They are useful for describing a range of values that satisfy multiple conditions at once, like a number being between two other numbers.

"AND" means a solution must satisfy both inequalities. "OR" means a solution must satisfy at least one of the inequalities.

How to Solve Compound Inequalities

  1. Identify the Joining Word: Is it "AND" or "OR"? This determines your solution set.
  2. Solve Each Inequality Separately: Isolate the variable in each part, just like a regular inequality.
  3. Combine the Solutions:
    • For "AND": Find the overlap where both solutions are true. Graphically, this is where the two number lines overlap.
    • For "OR": Combine all solutions from both inequalities. Graphically, you put both sets on the number line.
  4. Graph the Solution: Represent your final answer on a number line to visualize it.

Worked Examples

Example 1: "AND" Inequality

Solve and graph: -2 ≤ 3x + 1 < 7

  1. Subtract 1 from all three parts: -2 - 1 ≤ 3x + 1 - 1 < 7 - 1 → -3 ≤ 3x < 6
  2. Divide all three parts by 3: -3/3 ≤ 3x/3 < 6/3 → -1 ≤ x < 2
  3. Graph: A closed circle at -1, an open circle at 2, and shading in between.

Solution: [-1, 2)

Example 2: "OR" Inequality

Solve and graph: 2x + 3 < 1 OR x - 5 > 0

  1. Solve the first inequality: 2x < 1 - 3 → 2x < -2 → x < -1
  2. Solve the second inequality: x > 0 + 5 → x > 5
  3. Combine with "OR": The solution is all numbers less than -1 OR greater than 5.
  4. Graph: An arrow left from an open circle at -1, and an arrow right from an open circle at 5.

Solution: (-∞, -1) U (5, ∞)

Common Mistakes to Avoid ⚠️

Reversing the Inequality: Remember to flip the inequality sign only when you multiply or divide by a negative number.

Confusing "AND" and "OR": "AND" needs an overlap (like between two numbers). "OR" combines everything (like outside of two numbers).

Incorrect Graphing: Use an open circle for < or > and a closed circle for ≤ or ≥.

Tips & Tricks

The "Zappy Line" Method: For "AND" statements like -1 ≤ x < 2, draw a zappy line (or a thick line) on your number line from -1 to 2 to clearly show the included range.

Word Association: Think of "AND" as the strict guard—both conditions must be met. Think of "OR" as the flexible guard—either condition works.

How to Practice

  • Start with simple "AND" problems to master solving and graphing a single range.
  • Move on to "OR" problems, paying close attention to how the graph has two separate sections.
  • Create your own problems and solve them, or try to write the inequality from a given number line graph.
  • Use online practice tools that provide instant feedback on your steps and final answer.

Practice problems

6 of the 101, worked through step by step — try them before opening the answer.

1 |2x - 5| ≤ 7 = ?

Hint: Absolute value inequalities can be rewritten as compound inequalities. For |expression| ≤ number, it means the expression is between -number and number.

Show the answer

Answer: -1 ≤ x ≤ 6

  1. Recall the meaning of absolute value inequality. |A| ≤ k means: -k ≤ A ≤ k. So here, A = 2x - 5 and k = 7. That gives: -7 ≤ 2x - 5 ≤ 7.
  2. Isolate x in the middle part by adding 5 to all three parts of the inequality. -7 + 5 ≤ 2x - 5 + 5 ≤ 7 + 5 This simplifies to: -2 ≤ 2x ≤ 12
  3. Divide all three parts by 2. -2 / 2 ≤ 2x / 2 ≤ 12 / 2 Which gives: -1 ≤ x ≤ 6
  4. Final answer. The solution set is all x such that -1 ≤ x ≤ 6. We can check: if x = -1, |2(-1) - 5| = |-2 - 5| = |-7| = 7 ≤ 7, true. If x = 6, |2(6) - 5| = |12 - 5| = |7| = 7 ≤ 7, true. If x = 0, |0 - 5| = 5 ≤ 7, true.

We start with the inequality: |2x - 5| ≤ 7 So the answer is: -1 ≤ x ≤ 6

2 |3x - 7| ≥ 5 = ?

Hint: Absolute value inequalities require considering both positive and negative cases. For |expression| ≥ value, split into two separate inequalities.

Show the answer

Answer: x ≤ 2/3 or x ≥ 4

  1. For |3x - 7| ≥ 5, we need to consider two cases: Case 1: 3x - 7 ≥ 5 Case 2: 3x - 7 ≤ -5
  2. Solve Case 1: 3x - 7 ≥ 5 Add 7 to both sides: 3x ≥ 12 Divide both sides by 3: x ≥ 4
  3. Solve Case 2: 3x - 7 ≤ -5 Add 7 to both sides: 3x ≤ 2 Divide both sides by 3: x ≤ 2/3
  4. Combine the solutions x ≤ 2/3 or x ≥ 4 The final answer is x ≤ 2/3 or x ≥ 4.

3 |2x - 8| ≤ 6 = ?

Hint: Remember that absolute value inequalities can be rewritten as compound inequalities. For example, |y| ≤ k means -k ≤ y ≤ k.

Show the answer

Answer: 1 ≤ x ≤ 7

  1. Rewrite the absolute value inequality as a compound inequality: -6 ≤ 2x - 8 ≤ 6
  2. Add 8 to all three parts of the inequality: -6 + 8 ≤ 2x - 8 + 8 ≤ 6 + 8
  3. Simplify: 2 ≤ 2x ≤ 14
  4. Divide all parts by 2: 2/2 ≤ 2x/2 ≤ 14/2
  5. Simplify: 1 ≤ x ≤ 7

The answer is 1 ≤ x ≤ 7.

4 |2x - 5| ≤ 9 = ?

Hint: Remember that absolute value inequalities can be rewritten as compound inequalities. For |expression| ≤ number, it means the expression is between -number and number.

Show the answer

Answer: -2 ≤ x ≤ 7

  1. Rewrite the absolute value inequality as a compound inequality: -9 ≤ 2x - 5 ≤ 9
  2. Add 5 to all three parts of the inequality: -9 + 5 ≤ 2x - 5 + 5 ≤ 9 + 5
  3. Simplify: -4 ≤ 2x ≤ 14
  4. Divide all parts by 2: -4/2 ≤ 2x/2 ≤ 14/2
  5. Simplify: -2 ≤ x ≤ 7 The solution is -2 ≤ x ≤ 7.

5 |2x - 5| < 9 = ?

Hint: Remember that absolute value inequalities can be rewritten as compound inequalities. For |expression| < k, it means the expression is between -k and k.

Show the answer

Answer: -2 < x < 7

  1. The inequality |2x - 5| < 9 means that 2x - 5 is between -9 and 9.
  2. Write this as a compound inequality: -9 < 2x - 5 < 9
  3. Add 5 to all three parts: -9 + 5 < 2x - 5 + 5 < 9 + 5
  4. Simplify: -4 < 2x < 14
  5. Divide all parts by 2: -4/2 < 2x/2 < 14/2
  6. Simplify: -2 < x < 7 The solution is -2 < x < 7.

6 2x² - 8x - 10 = 0

Hint: This is a quadratic equation that can be solved by factoring, completing the square, or using the quadratic formula. Look for two numbers that multiply to give the product of the coefficient of x² and the constant term, and add to give the coefficient of x.

Show the answer

Answer: x = 5, x = -1

  1. Simplify the equation if possible** Notice that all coefficients (2, -8, -10) are divisible by 2. Divide the entire equation by 2: (2x²)/2 - (8x)/2 - 10/2 = 0/2 x² - 4x - 5 = 0 --- **
  2. Factor the quadratic** We need two numbers that multiply to -5 (the constant term) and add to -4 (the coefficient of x). Possible pairs for -5: 1 and -5 → 1 + (-5) = -4 ✔ This works. So: x² - 4x - 5 = (x - 5)(x + 1) = 0 --- **
  3. Apply the zero-product property** If (x - 5)(x + 1) = 0, then: x - 5 = 0 or x + 1 = 0 --- **
  4. Solve each equation** x - 5 = 0 → x = 5 x + 1 = 0 → x = -1 --- **Final Answer:** x = 5, x = -1

Let's solve the equation step by step. We have: 2x² - 8x - 10 = 0 --- **

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