Completing the Square
Grade 10 · Mathematics · Worksheet 1
- x² + 6x + 5 = 0 → (x + a)² + b = 0, find a and b Answer: ______________
- x² + 6x + 8 = 0 → (x + h)² + k = 0; h = ? Answer: ______________
- Complete the square: x² + 11x + 26 = 0 → (x + a)² = b, find a and b? Answer: ______________
- Kaia is designing a suspension bridge for a local park. The shape of the main cable between two towers can be modeled by the quadratic function h(x) = 3x^2 - 42x + 156, where h(x) is the height of the cable in meters above the bridge deck and x is the horizontal distance in meters from the left tower. Using the method of completing the square, rewrite the function in vertex form h(x) = a(x - p)^2 + q to find the minimum height of the cable above the deck and the horizontal distance from the left tower where this minimum occurs. Then, state the coordinates of the vertex. Answer: ______________
- A rectangular garden is designed with length (x + 8) meters and width (x + 2) meters. When the area is expressed in the form (x + p)² + q, what are the values of p and q? Answer: ______________
- Hana is designing a parabolic water fountain for a new park. The height of the water stream (in meters) above the fountain basin is given by the quadratic function h(x) = -2x^2 + 16x - 14, where x is the horizontal distance (in meters) from the nozzle. Using the method of completing the square, rewrite the function in vertex form h(x) = a(x - p)^2 + q to determine the maximum height of the water stream and the horizontal distance from the nozzle where this maximum occurs. Then, state the coordinates of the vertex. Answer: ______________
- Complete the square: x² - 12x + 35 = 0 → (x + a)² = b, find a and b? Answer: ______________
Answer Key & Explanations
Completing the Square · Grade 10 · Worksheet 1
- x² + 6x + 5 = 0 → (x + a)² + b = 0, find a and b Answer: a=3, b=-4 Solution: x^2 + 6x + 5 = 0 (x + a)^2 + b = 0 x^2 + 6x + 5 Take the coefficient of x, which is 6.
Full step-by-step solution
We start with the equation:
x^2 + 6x + 5 = 0
We want to rewrite it in the form:
(x + a)^2 + b = 0
---
**Step 1: Understand completing the square**
The general method:
x^2 + 6x + 5
Take the coefficient of x, which is 6.
Divide it by 2: 6/2 = 3
Square it: 3^2 = 9
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**Step 2: Add and subtract 9 inside the expression**
x^2 + 6x + 5
= x^2 + 6x + 9 - 9 + 5
---
**Step 3: Group the perfect square trinomial**
x^2 + 6x + 9 is (x + 3)^2
So we have:
(x^2 + 6x + 9) + (-9 + 5)
= (x + 3)^2 - 4
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**Step 4: Write in the required form**
(x + 3)^2 - 4 = 0
This matches (x + a)^2 + b = 0
So a = 3, b = -4
---
**Step 5: Check**
(x + 3)^2 - 4 = x^2 + 6x + 9 - 4 = x^2 + 6x + 5 ✔
---
**Final answer:**
a = 3, b = -4
- x² + 6x + 8 = 0 → (x + h)² + k = 0; h = ? Answer: 3 Solution: x^2 + 6x + 8 = 0 (x + h)^2 + k = 0 The expression (x + h)^2 expands to: x^2 + 2h x + h^2 So we need to match the coefficients of x^2 + 6x + 8 with x^2 + 2h x + h^2 + k. From x^2 + 6x + 8: Coefficient of x is 6.
Full step-by-step solution
We start with the equation:
x^2 + 6x + 8 = 0
We want to rewrite it in the form:
(x + h)^2 + k = 0
---
**Step 1: Understand the goal**
The expression (x + h)^2 expands to:
x^2 + 2h x + h^2
So we need to match the coefficients of x^2 + 6x + 8 with x^2 + 2h x + h^2 + k.
---
**Step 2: Compare coefficients of x**
From x^2 + 6x + 8:
Coefficient of x is 6.
From expansion: coefficient of x is 2h.
So:
2h = 6
h = 3
---
**Step 3: Check constant term**
From expansion: (x + h)^2 + k = x^2 + 2h x + h^2 + k.
Constant term in original equation: 8.
So: h^2 + k = 8.
Since h = 3:
9 + k = 8
k = -1
---
**Step 4: Verify**
(x + 3)^2 - 1 = x^2 + 6x + 9 - 1 = x^2 + 6x + 8.
Matches the original equation.
---
**Final answer:** h = 3
- Complete the square: x² + 11x + 26 = 0 → (x + a)² = b, find a and b? Answer: a = 11/2, b = -7/4 Solution: Start with x² + 11x + 26 = 0. Move the constant term to the right side: x² + 11x = -26. Take half of the coefficient of x (which is 11): 11/2.
Full step-by-step solution
Step 1: Start with x² + 11x + 26 = 0.
Step 2: Move the constant term to the right side: x² + 11x = -26.
Step 3: Take half of the coefficient of x (which is 11): 11/2.
Step 4: Square this value: (11/2)² = 121/4.
Step 5: Add 121/4 to both sides: x² + 11x + 121/4 = -26 + 121/4.
Step 6: The left side is now a perfect square: (x + 11/2)² = -26 + 121/4.
Step 7: Simplify the right side: -26 = -104/4, so -104/4 + 121/4 = 17/4.
Step 8: Therefore, (x + 11/2)² = 17/4. So a = 11/2 and b = 17/4.
The answer is a = 11/2, b = 17/4.
- Kaia is designing a suspension bridge for a local park. The shape of the main cable between two towers can be modeled by the quadratic function h(x) = 3x^2 - 42x + 156, where h(x) is the height of the cable in meters above the bridge deck and x is the horizontal distance in meters from the left tower. Using the method of completing the square, rewrite the function in vertex form h(x) = a(x - p)^2 + q to find the minimum height of the cable above the deck and the horizontal distance from the left tower where this minimum occurs. Then, state the coordinates of the vertex. Answer: Minimum height of 9 meters at a horizontal distance of 7 meters; vertex at (7, 9) Solution: Start with the function: h(x) = 3x^2 - 42x + 156 Factor out 3 from the x^2 and x terms: h(x) = 3(x^2 - 14x) + 156 Complete the square inside the parentheses. Take half of -14, which is -7, and square it to get 49.
Full step-by-step solution
Step 1: Start with the function: h(x) = 3x^2 - 42x + 156
Step 2: Factor out 3 from the x^2 and x terms: h(x) = 3(x^2 - 14x) + 156
Step 3: Complete the square inside the parentheses. Take half of -14, which is -7, and square it to get 49.
Step 4: Add and subtract 49 inside the parentheses: h(x) = 3(x^2 - 14x + 49 - 49) + 156
Step 5: Rewrite as: h(x) = 3[(x^2 - 14x + 49) - 49] + 156
Step 6: Factor the perfect square trinomial: h(x) = 3[(x - 7)^2 - 49] + 156
Step 7: Distribute the 3: h(x) = 3(x - 7)^2 - 147 + 156
Step 8: Simplify: h(x) = 3(x - 7)^2 + 9
Step 9: The vertex form is h(x) = 3(x - 7)^2 + 9, so the vertex is at (7, 9).
Step 10: Since the coefficient of (x - 7)^2 is positive, the parabola opens upward, and the vertex represents the minimum point.
Therefore, the minimum height of the cable is 9 meters above the deck, occurring at a horizontal distance of 7 meters from the left tower. The vertex is (7, 9).
- A rectangular garden is designed with length (x + 8) meters and width (x + 2) meters. When the area is expressed in the form (x + p)² + q, what are the values of p and q? Answer: p = 5, q = -9 Solution: Length = (x + 8) meters Width = (x + 2) meters Area = Length × Width Area = (x + 8)(x + 2) (x + 8)(x + 2) = x(x + 2) + 8(x + 2) = x² + 2x + 8x + 16 = x² + 10x + 16 So Area = x² + 10x + 16 We complete the square for x² + 10x + 16.
Full step-by-step solution
Let's go step-by-step.
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**Step 1: Write the area expression**
Length = (x + 8) meters
Width = (x + 2) meters
Area = Length × Width
Area = (x + 8)(x + 2)
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**Step 2: Expand the product**
(x + 8)(x + 2)
= x(x + 2) + 8(x + 2)
= x² + 2x + 8x + 16
= x² + 10x + 16
So Area = x² + 10x + 16
---
**Step 3: Write in the form (x + p)² + q**
We complete the square for x² + 10x + 16.
Take the x² + 10x part:
x² + 10x = (x + 5)² - 25
because (x + 5)² = x² + 10x + 25, so subtract 25 to get x² + 10x.
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**Step 4: Substitute back**
Area = [ (x + 5)² - 25 ] + 16
= (x + 5)² - 25 + 16
= (x + 5)² - 9
---
**Step 5: Identify p and q**
Comparing with (x + p)² + q:
p = 5
q = -9
---
**Final answer:** p = 5, q = -9
- Hana is designing a parabolic water fountain for a new park. The height of the water stream (in meters) above the fountain basin is given by the quadratic function h(x) = -2x^2 + 16x - 14, where x is the horizontal distance (in meters) from the nozzle. Using the method of completing the square, rewrite the function in vertex form h(x) = a(x - p)^2 + q to determine the maximum height of the water stream and the horizontal distance from the nozzle where this maximum occurs. Then, state the coordinates of the vertex. Answer: Maximum height of 18 meters at a horizontal distance of 4 meters; vertex at (4, 18) Solution: Start with the function: h(x) = -2x^2 + 16x - 14 Factor out -2 from the x^2 and x terms: h(x) = -2(x^2 - 8x) - 14 Complete the square inside the parentheses. Take half of -8, which is -4, and square it to get 16.
Full step-by-step solution
Step 1: Start with the function: h(x) = -2x^2 + 16x - 14
Step 2: Factor out -2 from the x^2 and x terms: h(x) = -2(x^2 - 8x) - 14
Step 3: Complete the square inside the parentheses. Take half of -8, which is -4, and square it to get 16.
Step 4: Add and subtract 16 inside the parentheses: h(x) = -2(x^2 - 8x + 16 - 16) - 14
Step 5: Rewrite as: h(x) = -2[(x^2 - 8x + 16) - 16] - 14
Step 6: Factor the perfect square trinomial: h(x) = -2[(x - 4)^2 - 16] - 14
Step 7: Distribute the -2: h(x) = -2(x - 4)^2 + 32 - 14
Step 8: Simplify: h(x) = -2(x - 4)^2 + 18
Step 9: The vertex form is h(x) = -2(x - 4)^2 + 18, so the vertex is at (4, 18).
Step 10: Since the coefficient of (x - 4)^2 is negative, the parabola opens downward, and the vertex represents the maximum point.
Therefore, the maximum height of the water stream is 18 meters, occurring at a horizontal distance of 4 meters from the nozzle. The vertex is (4, 18).
- Complete the square: x² - 12x + 35 = 0 → (x + a)² = b, find a and b? Answer: a = -6, b = 1 Solution: Start with x² - 12x + 35 = 0 Move the constant term to the right side: x² - 12x = -35 Take half of the coefficient of x: -12/2 = -6 Square this value: (-6)² = 36 Add 36 to both sides: x² - 12x + 36 = -35 + 36 Simplify the right side: x² - 12x + 36 = 1 Factor the left side as a perfect square: (x…
Full step-by-step solution
Step 1: Start with x² - 12x + 35 = 0
Step 2: Move the constant term to the right side: x² - 12x = -35
Step 3: Take half of the coefficient of x: -12/2 = -6
Step 4: Square this value: (-6)² = 36
Step 5: Add 36 to both sides: x² - 12x + 36 = -35 + 36
Step 6: Simplify the right side: x² - 12x + 36 = 1
Step 7: Factor the left side as a perfect square: (x - 6)² = 1
Step 8: This is in the form (x + a)² = b, where a = -6 and b = 1.
The answer is a = -6, b = 1.