Logarithms Solve Exponential
Grade 11 · Algebra · Worksheet 3
- A pharmaceutical company is testing a new drug that decays exponentially in the bloodstream. The concentration C(t) in milligrams per liter is modeled by C(t) = 80 × 2^(-0.1t), where t is time in hours. The drug becomes ineffective when its concentration drops below 5 mg/L. How many hours will it take for the drug to reach this ineffective concentration level? Answer: ______________
- Dr. Chen is studying bacterial growth in her lab. She observes that a colony of bacteria doubles in size every 4 hours. If she starts with 500 bacteria, how many hours will it take for the colony to reach 32,000 bacteria? Use logarithms to solve this exponential growth problem. Answer: ______________
- A radioactive substance decays according to the exponential model N(t) = N₀e^(-λt), where N₀ is the initial amount. A scientist observes that after 8 years, only 25% of the original substance remains. The scientist graphs the decay function on a coordinate plane where the x-axis represents time in years and the y-axis represents the percentage of substance remaining. Determine the decay constant λ (to three decimal places) using logarithmic methods. Answer: ______________
- 7^(2x - 1) = 27 Answer: ______________
- 7^(x - 3) = 45 Answer: ______________
- A sound wave's intensity I is measured in decibels using the formula β = 10 log(I/I₀), where I₀ = 10⁻¹² W/m² is the reference intensity. If a rock concert measures 115 decibels, what is the intensity I of the sound wave in W/m²? Answer: ______________
- 8^(x - 2) = 40 Answer: ______________
- A right triangle is drawn on a coordinate plane with vertices at (0,0), (x,0), and (0,8). The hypotenuse has length 17 units. Using the Pythagorean theorem, determine the value of x. Answer: ______________
Answer Key & Explanations
Logarithms Solve Exponential · Grade 11 · Worksheet 3
- A pharmaceutical company is testing a new drug that decays exponentially in the bloodstream. The concentration C(t) in milligrams per liter is modeled by C(t) = 80 × 2^(-0.1t), where t is time in hours. The drug becomes ineffective when its concentration drops below 5 mg/L. How many hours will it take for the drug to reach this ineffective concentration level? Answer: 40 Solution: Set up the equation with the given ineffective concentration: 80 × 2^(-0.1t) = 5 Divide both sides by 80 to isolate the exponential term: 2^(-0.1t) = 5/80 Simplify the fraction: 2^(-0.1t) = 1/16 Recognize that 1/16 = 2^(-4), so: 2^(-0.1t) = 2^(-4) Since the bases are equal, set the exponents…
Full step-by-step solution
Step 1: Set up the equation with the given ineffective concentration: 80 × 2^(-0.1t) = 5
Step 2: Divide both sides by 80 to isolate the exponential term: 2^(-0.1t) = 5/80
Step 3: Simplify the fraction: 2^(-0.1t) = 1/16
Step 4: Recognize that 1/16 = 2^(-4), so: 2^(-0.1t) = 2^(-4)
Step 5: Since the bases are equal, set the exponents equal: -0.1t = -4
Step 6: Divide both sides by -0.1: t = (-4)/(-0.1)
Step 7: Calculate: t = 40
The answer is 40 hours.
- Dr. Chen is studying bacterial growth in her lab. She observes that a colony of bacteria doubles in size every 4 hours. If she starts with 500 bacteria, how many hours will it take for the colony to reach 32,000 bacteria? Use logarithms to solve this exponential growth problem. Answer: 24 Solution: We start with 500 bacteria. The colony doubles every 4 hours. We want the time \( t \) (in hours) to reach 32,000 bacteria.
Full step-by-step solution
Let's solve this step-by-step.
---
**Step 1: Understand the problem**
We start with 500 bacteria.
The colony doubles every 4 hours.
We want the time \( t \) (in hours) to reach 32,000 bacteria.
---
**Step 2: Write the exponential growth formula**
The general formula for exponential growth is:
\[
N(t) = N_0 \times 2^{t / d}
\]
where:
\( N_0 \) = initial number of bacteria = 500
\( d \) = doubling time = 4 hours
\( N(t) \) = number of bacteria after \( t \) hours = 32,000
So:
\[
32,000 = 500 \times 2^{t / 4}
\]
---
**Step 3: Isolate the exponential term**
Divide both sides by 500:
\[
\frac{32,000}{500} = 2^{t / 4}
\]
\[
64 = 2^{t / 4}
\]
---
**Step 4: Recognize powers of 2**
\( 64 = 2^6 \), so:
\[
2^{t / 4} = 2^6
\]
---
**Step 5: Equate exponents**
Since the bases are the same (base 2), we can equate the exponents:
\[
\frac{t}{4} = 6
\]
---
**Step 6: Solve for \( t \)**
Multiply both sides by 4:
\[
t = 6 \times 4 = 24
\]
---
**Step 7: Conclusion**
It will take **24 hours** for the colony to grow from 500 to 32,000 bacteria.
---
**Final answer:** 24
- A radioactive substance decays according to the exponential model N(t) = N₀e^(-λt), where N₀ is the initial amount. A scientist observes that after 8 years, only 25% of the original substance remains. The scientist graphs the decay function on a coordinate plane where the x-axis represents time in years and the y-axis represents the percentage of substance remaining. Determine the decay constant λ (to three decimal places) using logarithmic methods. Answer: 0.173 Solution: We are given: N(t) = N0 * e^(-λt) After 8 years, 25% remains, so N(8) = 0.25 * N0. Substitute into the equation. 0.25 * N0 = N0 * e^(-λ * 8) Divide both sides by N0 (N0 > 0).
Full step-by-step solution
We are given: N(t) = N0 * e^(-λt)
After 8 years, 25% remains, so N(8) = 0.25 * N0.
Step 1: Substitute into the equation.
0.25 * N0 = N0 * e^(-λ * 8)
Step 2: Divide both sides by N0 (N0 > 0).
0.25 = e^(-8λ)
Step 3: Take natural logarithm of both sides.
ln(0.25) = ln(e^(-8λ))
ln(0.25) = -8λ * ln(e)
Since ln(e) = 1, we have:
ln(0.25) = -8λ
Step 4: Solve for λ.
λ = - ln(0.25) / 8
Step 5: Calculate ln(0.25).
0.25 = 1/4, so ln(0.25) = ln(1) - ln(4) = 0 - ln(4) = -ln(4).
ln(4) = ln(2^2) = 2 * ln(2) ≈ 2 * 0.693147 = 1.386294
So ln(0.25) ≈ -1.386294
Step 6: Substitute into λ.
λ = - (-1.386294) / 8
λ = 1.386294 / 8
λ ≈ 0.17328675
Step 7: Round to three decimal places.
0.17328675 → 0.173
Final answer: λ ≈ 0.173
- 7^(2x - 1) = 27 Answer: x = (log₇(27) + 1) / 2 ≈ 1.347 Solution: Take the natural logarithm of both sides: ln(7^(2x - 1)) = ln(27) Use the power rule of logarithms: (2x - 1) * ln(7) = ln(27) Divide both sides by ln(7): 2x - 1 = ln(27) / ln(7) Add 1 to both sides: 2x = ln(27) / ln(7) + 1 Divide both sides by 2: x = (ln(27) / ln(7) + 1) / 2 Using a calculator,…
Full step-by-step solution
Step 1: Take the natural logarithm of both sides: ln(7^(2x - 1)) = ln(27)
Step 2: Use the power rule of logarithms: (2x - 1) * ln(7) = ln(27)
Step 3: Divide both sides by ln(7): 2x - 1 = ln(27) / ln(7)
Step 4: Add 1 to both sides: 2x = ln(27) / ln(7) + 1
Step 5: Divide both sides by 2: x = (ln(27) / ln(7) + 1) / 2
Step 6: Using a calculator, ln(27) ≈ 3.2958, ln(7) ≈ 1.9459, so ln(27)/ln(7) ≈ 1.693. Then x ≈ (1.693 + 1) / 2 = 2.693 / 2 = 1.3465. Rounded to three decimal places, x ≈ 1.347.
- 7^(x - 3) = 45 Answer: x = 3 + log_7(45) ≈ 4.956 Solution: Take the natural logarithm (or common logarithm) of both sides: ln(7^(x-3)) = ln(45). Divide both sides by ln(7): x - 3 = ln(45) / ln(7). Add 3 to both sides: x = 3 + ln(45) / ln(7).
Full step-by-step solution
Step 1: Take the natural logarithm (or common logarithm) of both sides: ln(7^(x-3)) = ln(45).
Step 2: Apply the power rule of logarithms: (x - 3) * ln(7) = ln(45).
Step 3: Divide both sides by ln(7): x - 3 = ln(45) / ln(7).
Step 4: Add 3 to both sides: x = 3 + ln(45) / ln(7).
Step 5: Calculate using a calculator: ln(45) ≈ 3.80666, ln(7) ≈ 1.94591, so ln(45)/ln(7) ≈ 1.956. Then x ≈ 3 + 1.956 = 4.956.
The exact answer is x = 3 + log_7(45), and the approximate decimal answer is x ≈ 4.956.
- A sound wave's intensity I is measured in decibels using the formula β = 10 log(I/I₀), where I₀ = 10⁻¹² W/m² is the reference intensity. If a rock concert measures 115 decibels, what is the intensity I of the sound wave in W/m²? Answer: 0.316227766 Solution: Write the given formula with the known values: 115 = 10 log(I/10⁻¹²) Divide both sides by 10: 11.5 = log(I/10⁻¹²) Convert from logarithmic to exponential form: I/10⁻¹² = 10¹¹·⁵ Multiply both sides by 10⁻¹²: I = 10¹¹·⁵ × 10⁻¹² Simplify using exponent rules: I = 10¹¹·⁵⁻¹² = 10⁻⁰·⁵ Calculate 10⁻⁰·⁵…
Full step-by-step solution
Step 1: Write the given formula with the known values: 115 = 10 log(I/10⁻¹²)
Step 2: Divide both sides by 10: 11.5 = log(I/10⁻¹²)
Step 3: Convert from logarithmic to exponential form: I/10⁻¹² = 10¹¹·⁵
Step 4: Multiply both sides by 10⁻¹²: I = 10¹¹·⁵ × 10⁻¹²
Step 5: Simplify using exponent rules: I = 10¹¹·⁵⁻¹² = 10⁻⁰·⁵
Step 6: Calculate 10⁻⁰·⁵ = 1/10⁰·⁵ = 1/√10 ≈ 1/3.16227766 ≈ 0.316227766
The intensity is approximately 0.316 W/m².
- 8^(x - 2) = 40 Answer: x ≈ 3.77 Solution: Take the natural log of both sides: ln(8^(x - 2)) = ln(40) Use the power rule: (x - 2) * ln(8) = ln(40) Divide both sides by ln(8): x - 2 = ln(40) / ln(8) Calculate the logs: ln(40) ≈ 3.6889, ln(8) ≈ 2.0794 Divide: 3.6889 / 2.0794 ≈ 1.774 Add 2 to both sides: x ≈ 1.774 + 2 = 3.774 The answer is…
Full step-by-step solution
Step 1: Take the natural log of both sides: ln(8^(x - 2)) = ln(40)
Step 2: Use the power rule: (x - 2) * ln(8) = ln(40)
Step 3: Divide both sides by ln(8): x - 2 = ln(40) / ln(8)
Step 4: Calculate the logs: ln(40) ≈ 3.6889, ln(8) ≈ 2.0794
Step 5: Divide: 3.6889 / 2.0794 ≈ 1.774
Step 6: Add 2 to both sides: x ≈ 1.774 + 2 = 3.774
The answer is x ≈ 3.77 (rounded to two decimal places).
- A right triangle is drawn on a coordinate plane with vertices at (0,0), (x,0), and (0,8). The hypotenuse has length 17 units. Using the Pythagorean theorem, determine the value of x. Answer: 15 Solution: - A = (0, 0) - B = (x, 0) - C = (0, 8) Since B is on the x-axis and C is on the y-axis, the right angle is at A = (0, 0). - Side AB is along the x-axis from (0, 0) to (x, 0). Length of AB = |x - 0| = x.
Full step-by-step solution
Let's go step-by-step.
---
**Step 1: Understand the triangle's vertices**
We have a right triangle with vertices at:
- A = (0, 0)
- B = (x, 0)
- C = (0, 8)
Since B is on the x-axis and C is on the y-axis, the right angle is at A = (0, 0).
---
**Step 2: Identify the legs of the triangle**
- Side AB is along the x-axis from (0, 0) to (x, 0).
Length of AB = |x - 0| = x.
- Side AC is along the y-axis from (0, 0) to (0, 8).
Length of AC = 8.
- Side BC is the hypotenuse, length = 17.
---
**Step 3: Apply the Pythagorean theorem**
Pythagorean theorem:
(leg1)^2 + (leg2)^2 = (hypotenuse)^2
Here:
AB^2 + AC^2 = BC^2
So:
x^2 + 8^2 = 17^2
---
**Step 4: Calculate the squares**
8^2 = 64
17^2 = 289
So:
x^2 + 64 = 289
---
**Step 5: Solve for x^2**
x^2 = 289 - 64
x^2 = 225
---
**Step 6: Solve for x**
x = sqrt(225)
x = 15 or x = -15
But since x is a length (distance from (0,0) to (x,0) along the x-axis), we take the positive value:
x = 15
---
**Final answer:** x = 15