P(rolling a 3 or 5 on a fair six-sided die) = ?Answer: ______________
P(drawing a card numbered with an odd number from a bag containing cards numbered 1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21) = ?Answer: ______________
A circular dartboard has a radius of 18 inches. The bullseye is a smaller circle in the center with a radius of 3 inches. If a dart hits the dartboard at a completely random point, what is the probability that it lands in the bullseye? Express your answer as a fraction in simplest form.Answer: ______________
A circular dartboard has a radius of 12 inches. The bullseye is a smaller circle at the center with a radius of 2 inches. If a randomly thrown dart hits the dartboard, what is the probability that it lands in the bullseye? (Use π = 3.14)Answer: ______________
Noah is organizing a school raffle where 150 tickets are sold. There are 3 grand prizes, 8 second prizes, and 15 consolation prizes. If Noah buys one ticket, what is the probability that he wins any prize? Express your answer as a simplified fraction.Answer: ______________
lessonbunny.com
Answer Key & Explanations
Probability Concepts · Grade 7 · Worksheet 2
P(rolling a 3 or 5 on a fair six-sided die) = ?Answer: 1/3 Solution: We have a fair six-sided die. The possible outcomes when rolling it are: 1, 2, 3, 4, 5, 6. We want the probability of rolling a 3 OR a 5.Full step-by-step solution
Step 1: Understand the problem.
We have a fair six-sided die. The possible outcomes when rolling it are: 1, 2, 3, 4, 5, 6.
We want the probability of rolling a 3 OR a 5.
Step 2: Recall the formula for probability.
Probability = (Number of favorable outcomes) / (Total number of possible outcomes).
Step 3: Identify the total number of possible outcomes.
Since the die has six sides, there are 6 possible outcomes. So, total outcomes = 6.
Step 4: Identify the number of favorable outcomes.
Favorable outcomes are the outcomes we want, which are rolling a 3 OR rolling a 5.
- Rolling a 3 is one favorable outcome.
- Rolling a 5 is another favorable outcome.
So, total favorable outcomes = 1 + 1 = 2.
Step 5: Calculate the probability.
Probability = (Number of favorable outcomes) / (Total number of possible outcomes) = 2 / 6.
Step 6: Simplify the fraction.
The fraction 2/6 can be simplified by dividing the numerator and denominator by 2.
2 divided by 2 is 1.
6 divided by 2 is 3.
So, 2/6 simplifies to 1/3.
Step 7: State the final answer.
Therefore, the probability of rolling a 3 or a 5 is 1/3.
P(drawing a card numbered with an odd number from a bag containing cards numbered 1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21) = ?Answer: 1 Solution: Count the total number of cards in the bag. The cards are numbered 1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21. That is 11 cards total.Full step-by-step solution
Step 1: Count the total number of cards in the bag. The cards are numbered 1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21. That is 11 cards total.
Step 2: Identify the favorable outcomes. The problem asks for drawing a card with an odd number. All numbers listed are odd, so all 11 cards are favorable.
Step 3: Calculate the probability. Probability = (Number of favorable outcomes) / (Total number of outcomes) = 11/11.
Step 4: Simplify the fraction. 11/11 = 1.
The answer is 1.
A circular dartboard has a radius of 18 inches. The bullseye is a smaller circle in the center with a radius of 3 inches. If a dart hits the dartboard at a completely random point, what is the probability that it lands in the bullseye? Express your answer as a fraction in simplest form.Answer: 1/36 Solution: We have a circular dartboard with radius 18 inches. The bullseye is a smaller circle in the center with radius 3 inches. A dart hits a random point on the dartboard.Full step-by-step solution
Step 1: Understand the problem.
We have a circular dartboard with radius 18 inches. The bullseye is a smaller circle in the center with radius 3 inches. A dart hits a random point on the dartboard. We want the probability that it lands in the bullseye.
Step 2: Recall probability for areas.
When points are chosen randomly over an area, the probability of hitting a specific region is:
(Area of the specific region) / (Total area available)
Step 3: Find the area of the whole dartboard.
The area of a circle is pi * r^2.
Total area = pi * (18)^2 = pi * 324.
Step 4: Find the area of the bullseye.
Bullseye area = pi * (3)^2 = pi * 9.
Step 5: Write the probability.
Probability = (Bullseye area) / (Total area) = (pi * 9) / (pi * 324).
Step 6: Simplify.
The pi cancels out: 9 / 324.
Step 7: Reduce the fraction.
Both 9 and 324 are divisible by 9:
9 ÷ 9 = 1
324 ÷ 9 = 36
So, 9/324 = 1/36.
Step 8: Final answer.
The probability is 1/36.
A circular dartboard has a radius of 12 inches. The bullseye is a smaller circle at the center with a radius of 2 inches. If a randomly thrown dart hits the dartboard, what is the probability that it lands in the bullseye? (Use π = 3.14)Answer: 0.0278 Solution: We have a circular dartboard with radius 12 inches. The bullseye is a smaller circle at the center with radius 2 inches.Full step-by-step solution
Step 1: Understand the problem
We have a circular dartboard with radius 12 inches. The bullseye is a smaller circle at the center with radius 2 inches. A dart hits the dartboard randomly, so the probability of hitting the bullseye is the ratio of the area of the bullseye to the area of the whole dartboard.
Step 2: Recall the area formula for a circle
Area of a circle = π × r²
Step 3: Calculate the area of the dartboard
Radius of dartboard, R = 12 inches
Area of dartboard = π × R² = 3.14 × (12)²
First compute 12² = 144
So Area of dartboard = 3.14 × 144
3.14 × 144 = 3.14 × 100 + 3.14 × 44
= 314 + 138.16 = 452.16 square inches
Step 4: Calculate the area of the bullseye
Radius of bullseye, r = 2 inches
Area of bullseye = π × r² = 3.14 × (2)²
2² = 4
So Area of bullseye = 3.14 × 4 = 12.56 square inches
Step 5: Compute the probability
Probability = (Area of bullseye) / (Area of dartboard)
= 12.56 / 452.16
Step 6: Simplify the division
First, let's divide numerator and denominator by 0.01 to make it easier:
1256 / 45216
Now divide both by 8:
1256 ÷ 8 = 157
45216 ÷ 8 = 5652
So we have 157 / 5652
Step 7: Perform the division numerically
12.56 ÷ 452.16
We can compute:
452.16 × 0.027 = 12.20832
12.56 − 12.20832 = 0.35168
Now 452.16 × 0.0007 = 0.316512
0.35168 − 0.316512 = 0.035168
452.16 × 0.000077 ≈ 0.034816
Remainder is small, so approximately 0.027777...
Step 8: Round to four decimal places
0.027777... ≈ 0.0278
Step 9: Final answer
The probability that the dart lands in the bullseye is 0.0278.
Noah is organizing a school raffle where 150 tickets are sold. There are 3 grand prizes, 8 second prizes, and 15 consolation prizes. If Noah buys one ticket, what is the probability that he wins any prize? Express your answer as a simplified fraction.Answer: 13/75 Solution: Grand prizes: 3 tickets Second prizes: 8 tickets Consolation prizes: 15 tickets Total prize tickets = 3 + 8 + 15 = 26 Total tickets sold = 150 Probability = (Number of favorable outcomes) / (Total possible outcomes) Probability = 26/150 Both numerator and denominator can be divided by 2 26 ÷ 2 =…Full step-by-step solution
Step 1: Find the total number of prize tickets
Grand prizes: 3 tickets
Second prizes: 8 tickets
Consolation prizes: 15 tickets
Total prize tickets = 3 + 8 + 15 = 26
Step 2: Find the total number of tickets
Total tickets sold = 150
Step 3: Calculate the probability
Probability = (Number of favorable outcomes) / (Total possible outcomes)
Probability = 26/150
Step 4: Simplify the fraction
Both numerator and denominator can be divided by 2
26 ÷ 2 = 13
150 ÷ 2 = 75
Simplified fraction = 13/75
The answer is 13/75.